30110012113 has 2 divisors, whose sum is σ = 30110012114. Its totient is φ = 30110012112.

The previous prime is 30110012083. The next prime is 30110012131. The reversal of 30110012113 is 31121001103.

Together with next prime (30110012131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16408841409 + 13701170704 = 128097^2 + 117052^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-30110012113 is a prime.

It is a super-2 number, since 2×30110012113² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 30110012093 and 30110012102.

It is not a weakly prime, because it can be changed into another prime (30110012143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15055006056 + 15055006057.

It is an arithmetic number, because the mean of its divisors is an integer number (15055006057).

Almost surely, 2^30110012113 is an apocalyptic number.

It is an amenable number.

30110012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

30110012113 is an equidigital number, since it uses as much as digits as its factorization.

30110012113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 30110012113 its reverse (31121001103), we get a palindrome (61231013216).

The spelling of 30110012113 in words is "thirty billion, one hundred ten million, twelve thousand, one hundred thirteen".