Base | Representation |
---|---|
bin | 1101101100010100010011… |
… | …11010000110010000000111 |
3 | 10221121111021001221011012011 |
4 | 12312022021322012100013 |
5 | 12421310322310003021 |
6 | 144012205303235051 |
7 | 6225243502664215 |
oct | 666121172062007 |
9 | 127544231834164 |
10 | 30110034453511 |
11 | 9659659533641 |
12 | 3463639748a87 |
13 | 13a5496b1023c |
14 | 761494d7bcb5 |
15 | 37336ee29de1 |
hex | 1b6289e86407 |
30110034453511 has 2 divisors, whose sum is σ = 30110034453512. Its totient is φ = 30110034453510.
The previous prime is 30110034453487. The next prime is 30110034453601. The reversal of 30110034453511 is 11535443001103.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30110034453511 is a prime.
It is a super-2 number, since 2×301100344535112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30110034450511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15055017226755 + 15055017226756.
It is an arithmetic number, because the mean of its divisors is an integer number (15055017226756).
Almost surely, 230110034453511 is an apocalyptic number.
30110034453511 is a deficient number, since it is larger than the sum of its proper divisors (1).
30110034453511 is an equidigital number, since it uses as much as digits as its factorization.
30110034453511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 30110034453511 its reverse (11535443001103), we get a palindrome (41645477454614).
The spelling of 30110034453511 in words is "thirty trillion, one hundred ten billion, thirty-four million, four hundred fifty-three thousand, five hundred eleven".
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