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30110223113 = 58751295099
BaseRepresentation
bin11100000010101101…
…011000101100001001
32212201102200211001122
4130002231120230021
5443131204114423
621455450325025
72114105450015
oct340255305411
985642624048
1030110223113
1111851488313
125a03a29775
132abb177b89
141658d3b545
15bb364c8c8
hex702b58b09

30110223113 has 4 divisors (see below), whose sum is σ = 30161518800. Its totient is φ = 30058927428.

The previous prime is 30110223109. The next prime is 30110223131. The reversal of 30110223113 is 31132201103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 30110223113 - 22 = 30110223109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 30110223091 and 30110223100.

It is not an unprimeable number, because it can be changed into a prime (30110223103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25646963 + ... + 25648136.

It is an arithmetic number, because the mean of its divisors is an integer number (7540379700).

Almost surely, 230110223113 is an apocalyptic number.

It is an amenable number.

30110223113 is a deficient number, since it is larger than the sum of its proper divisors (51295687).

30110223113 is an equidigital number, since it uses as much as digits as its factorization.

30110223113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51295686.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 30110223113 its reverse (31132201103), we get a palindrome (61242424216).

The spelling of 30110223113 in words is "thirty billion, one hundred ten million, two hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 587 51295099 30110223113