Base | Representation |
---|---|
bin | 1101101100010110000110… |
… | …11101010111011000000001 |
3 | 10221121120202100202222222021 |
4 | 12312023003131113120001 |
5 | 12421314312000000001 |
6 | 144012445154241441 |
7 | 6225306436000444 |
oct | 666130335273001 |
9 | 127546670688867 |
10 | 30111000000001 |
11 | 965a004564a48 |
12 | 3463868b86281 |
13 | 13a55bbb7631b |
14 | 7615472bb65b |
15 | 3733c9aa2ba1 |
hex | 1b62c3757601 |
30111000000001 has 2 divisors, whose sum is σ = 30111000000002. Its totient is φ = 30111000000000.
The previous prime is 30110999999987. The next prime is 30111000000013. The reversal of 30111000000001 is 10000000011103.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30105193712400 + 5806287601 = 5486820^2 + 76199^2 .
It is a cyclic number.
It is not a de Polignac number, because 30111000000001 - 215 = 30110999967233 is a prime.
It is not a weakly prime, because it can be changed into another prime (30111000000071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15055500000000 + 15055500000001.
It is an arithmetic number, because the mean of its divisors is an integer number (15055500000001).
Almost surely, 230111000000001 is an apocalyptic number.
It is an amenable number.
30111000000001 is a deficient number, since it is larger than the sum of its proper divisors (1).
30111000000001 is an equidigital number, since it uses as much as digits as its factorization.
30111000000001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 7.
Adding to 30111000000001 its reverse (10000000011103), we get a palindrome (40111000011104).
The spelling of 30111000000001 in words is "thirty trillion, one hundred eleven billion, one", and thus it is an aban number.
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