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30113002013 = 49161329943
BaseRepresentation
bin11100000010110111…
…111111001000011101
32212201121220222222212
4130002313333020131
5443132412031023
621500030050205
72114141202533
oct340267771035
985647828885
1030113002013
1111853006126
125a04949965
132abb90b9b3
141659462153
15bb39eae78
hex702dff21d

30113002013 has 4 divisors (see below), whose sum is σ = 30174332448. Its totient is φ = 30051671580.

The previous prime is 30113001913. The next prime is 30113002033. The reversal of 30113002013 is 31020031103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31020031103 = 37838379219.

It is a cyclic number.

It is not a de Polignac number, because 30113002013 - 28 = 30113001757 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (30113002033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30664481 + ... + 30665462.

It is an arithmetic number, because the mean of its divisors is an integer number (7543583112).

Almost surely, 230113002013 is an apocalyptic number.

It is an amenable number.

30113002013 is a deficient number, since it is larger than the sum of its proper divisors (61330435).

30113002013 is an equidigital number, since it uses as much as digits as its factorization.

30113002013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61330434.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 30113002013 its reverse (31020031103), we get a palindrome (61133033116).

The spelling of 30113002013 in words is "thirty billion, one hundred thirteen million, two thousand, thirteen".

Divisors: 1 491 61329943 30113002013