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30113305141 = 39383764627
BaseRepresentation
bin11100000010111001…
…001001001000110101
32212201122111101210211
4130002321021020311
5443133001231031
621500040345421
72114143604353
oct340271111065
985648441724
1030113305141
11118531a2947
125a04a75271
132abb9b696a
1416595007d3
15bb3a5abb1
hex702e49235

30113305141 has 4 divisors (see below), whose sum is σ = 30114109152. Its totient is φ = 30112501132.

The previous prime is 30113305129. The next prime is 30113305163. The reversal of 30113305141 is 14150331103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 30113305141 - 211 = 30113303093 is a prime.

It is a super-2 number, since 2×301133051412 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (30113305111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342931 + ... + 421696.

It is an arithmetic number, because the mean of its divisors is an integer number (7528527288).

Almost surely, 230113305141 is an apocalyptic number.

It is an amenable number.

30113305141 is a deficient number, since it is larger than the sum of its proper divisors (804011).

30113305141 is an equidigital number, since it uses as much as digits as its factorization.

30113305141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 804010.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 30113305141 its reverse (14150331103), we get a palindrome (44263636244).

The spelling of 30113305141 in words is "thirty billion, one hundred thirteen million, three hundred five thousand, one hundred forty-one".

Divisors: 1 39383 764627 30113305141