Search a number
-
+
30120220113 = 310040073371
BaseRepresentation
bin11100000011010011…
…100001010111010001
32212202010111201100220
4130003103201113101
5443141234020423
621500444503253
72114256434544
oct340323412721
985663451326
1030120220113
11118570961a5
125a0724ab29
132ac0268269
14165a3c085b
15bb44749e3
hex7034e15d1

30120220113 has 4 divisors (see below), whose sum is σ = 40160293488. Its totient is φ = 20080146740.

The previous prime is 30120220061. The next prime is 30120220129. The reversal of 30120220113 is 31102202103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 30120220113 - 29 = 30120219601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 30120220092 and 30120220101.

It is not an unprimeable number, because it can be changed into a prime (30120220133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5020036683 + ... + 5020036688.

It is an arithmetic number, because the mean of its divisors is an integer number (10040073372).

Almost surely, 230120220113 is an apocalyptic number.

It is an amenable number.

30120220113 is a deficient number, since it is larger than the sum of its proper divisors (10040073375).

30120220113 is a wasteful number, since it uses less digits than its factorization.

30120220113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10040073374.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 30120220113 its reverse (31102202103), we get a palindrome (61222422216).

The spelling of 30120220113 in words is "thirty billion, one hundred twenty million, two hundred twenty thousand, one hundred thirteen".

Divisors: 1 3 10040073371 30120220113