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30121431433 is a prime number
BaseRepresentation
bin11100000011011000…
…001001000110001001
32212202012210020222121
4130003120021012021
5443142041301213
621500530451241
72114302641232
oct340330110611
985665706877
1030121431433
1111857843295
125a07733b21
132ac05a0712
14165a618089
15bb461388d
hex703609189

30121431433 has 2 divisors, whose sum is σ = 30121431434. Its totient is φ = 30121431432.

The previous prime is 30121431427. The next prime is 30121431463. The reversal of 30121431433 is 33413412103.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30058197129 + 63234304 = 173373^2 + 7952^2 .

It is a cyclic number.

It is not a de Polignac number, because 30121431433 - 217 = 30121300361 is a prime.

It is a super-3 number, since 3×301214314333 (a number of 32 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 30121431398 and 30121431407.

It is not a weakly prime, because it can be changed into another prime (30121431463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15060715716 + 15060715717.

It is an arithmetic number, because the mean of its divisors is an integer number (15060715717).

Almost surely, 230121431433 is an apocalyptic number.

It is an amenable number.

30121431433 is a deficient number, since it is larger than the sum of its proper divisors (1).

30121431433 is an equidigital number, since it uses as much as digits as its factorization.

30121431433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 30121431433 its reverse (33413412103), we get a palindrome (63534843536).

The spelling of 30121431433 in words is "thirty billion, one hundred twenty-one million, four hundred thirty-one thousand, four hundred thirty-three".