Base | Representation |
---|---|
bin | 101011110101011100111… |
… | …100000001000000011101 |
3 | 101122222100112210210020021 |
4 | 223311130330001000131 |
5 | 343323223303424013 |
6 | 10223502414152141 |
7 | 430430243446354 |
oct | 53653474010035 |
9 | 11588315723207 |
10 | 3012331311133 |
11 | a61582548301 |
12 | 4079877b2651 |
13 | 18b0a5506201 |
14 | a5b2491899b |
15 | 5355710aa8d |
hex | 2bd5cf0101d |
3012331311133 has 16 divisors (see below), whose sum is σ = 3164231702016. Its totient is φ = 2862193443120.
The previous prime is 3012331311107. The next prime is 3012331311173. The reversal of 3012331311133 is 3311131332103.
It is a cyclic number.
It is not a de Polignac number, because 3012331311133 - 225 = 3012297756701 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3012331311098 and 3012331311107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3012331311173) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7031266 + ... + 7447372.
It is an arithmetic number, because the mean of its divisors is an integer number (197764481376).
Almost surely, 23012331311133 is an apocalyptic number.
It is an amenable number.
3012331311133 is a deficient number, since it is larger than the sum of its proper divisors (151900390883).
3012331311133 is a wasteful number, since it uses less digits than its factorization.
3012331311133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 418224.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 3012331311133 its reverse (3311131332103), we get a palindrome (6323462643236).
The spelling of 3012331311133 in words is "three trillion, twelve billion, three hundred thirty-one million, three hundred eleven thousand, one hundred thirty-three".
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