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301431000001 = 1993151244857
BaseRepresentation
bin1000110001011101011…
…00000000101111000001
31001211001020121100201011
410120232230000233001
514414312314000001
6350250412240521
730530512140115
oct4305654005701
91054036540634
10301431000001
11106921a3982a
124a504770141
132256a442581
1410837203745
157c93128d51
hex462eb00bc1

301431000001 has 4 divisors (see below), whose sum is σ = 301582246852. Its totient is φ = 301279753152.

The previous prime is 301430999999. The next prime is 301431000037. The reversal of 301431000001 is 100000134103.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 204825035776 + 96605964225 = 452576^2 + 310815^2 .

It is a cyclic number.

It is not a de Polignac number, because 301431000001 - 21 = 301430999999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (301431004001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75620436 + ... + 75624421.

It is an arithmetic number, because the mean of its divisors is an integer number (75395561713).

Almost surely, 2301431000001 is an apocalyptic number.

It is an amenable number.

301431000001 is a deficient number, since it is larger than the sum of its proper divisors (151246851).

301431000001 is a wasteful number, since it uses less digits than its factorization.

301431000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151246850.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 301431000001 its reverse (100000134103), we get a palindrome (401431134104).

The spelling of 301431000001 in words is "three hundred one billion, four hundred thirty-one million, one", and thus it is an aban number.

Divisors: 1 1993 151244857 301431000001