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30144011113 is a prime number
BaseRepresentation
bin11100000100101110…
…010001101101101001
32212210210021102111001
4130010232101231221
5443213331323423
621503054435001
72114665603216
oct340456215551
985723242431
1030144011113
1111869565787
125a13202a61
132ac5178088
14165d614b0d
15bb65c3cad
hex704b91b69

30144011113 has 2 divisors, whose sum is σ = 30144011114. Its totient is φ = 30144011112.

The previous prime is 30144011101. The next prime is 30144011129. The reversal of 30144011113 is 31111044103.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26481703824 + 3662307289 = 162732^2 + 60517^2 .

It is a cyclic number.

It is not a de Polignac number, because 30144011113 - 221 = 30141913961 is a prime.

It is a super-2 number, since 2×301440111132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (30144011153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15072005556 + 15072005557.

It is an arithmetic number, because the mean of its divisors is an integer number (15072005557).

Almost surely, 230144011113 is an apocalyptic number.

It is an amenable number.

30144011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

30144011113 is an equidigital number, since it uses as much as digits as its factorization.

30144011113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 30144011113 its reverse (31111044103), we get a palindrome (61255055216).

The spelling of 30144011113 in words is "thirty billion, one hundred forty-four million, eleven thousand, one hundred thirteen".