Base | Representation |
---|---|
bin | 101011111000000100101… |
… | …001111001000000010011 |
3 | 101200020121122111200212211 |
4 | 223320010221321000103 |
5 | 343400004123211201 |
6 | 10225045532132551 |
7 | 430560051520033 |
oct | 53700451710023 |
9 | 11606548450784 |
10 | 3015145132051 |
11 | a62796905638 |
12 | 408432007157 |
13 | 18b4334621c0 |
14 | a5d104d98c3 |
15 | 5366e175651 |
hex | 2be04a79013 |
3015145132051 has 4 divisors (see below), whose sum is σ = 3247079372992. Its totient is φ = 2783210891112.
The previous prime is 3015145132037. The next prime is 3015145132081. The reversal of 3015145132051 is 1502315415103.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3015145132051 - 217 = 3015145000979 is a prime.
It is a super-2 number, since 2×30151451320512 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3015145132081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115967120451 + ... + 115967120476.
It is an arithmetic number, because the mean of its divisors is an integer number (811769843248).
Almost surely, 23015145132051 is an apocalyptic number.
3015145132051 is a deficient number, since it is larger than the sum of its proper divisors (231934240941).
3015145132051 is a wasteful number, since it uses less digits than its factorization.
3015145132051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 231934240940.
The product of its (nonzero) digits is 9000, while the sum is 31.
The spelling of 3015145132051 in words is "three trillion, fifteen billion, one hundred forty-five million, one hundred thirty-two thousand, fifty-one".
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