Base | Representation |
---|---|
bin | 11100001000010011… |
… | …001100100101111001 |
3 | 2212221222012020201122 |
4 | 130020103030211321 |
5 | 443324212133423 |
6 | 21513040555025 |
7 | 2116324641410 |
oct | 341023144571 |
9 | 85858166648 |
10 | 30204021113 |
11 | 1189a423122 |
12 | 5a2b322a75 |
13 | 2b04729756 |
14 | 1667596477 |
15 | bbb9c98c8 |
hex | 7084cc979 |
30204021113 has 4 divisors (see below), whose sum is σ = 34518881280. Its totient is φ = 25889160948.
The previous prime is 30204021083. The next prime is 30204021119. The reversal of 30204021113 is 31112040203.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 30204021113 - 218 = 30203758969 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 30204021091 and 30204021100.
It is not an unprimeable number, because it can be changed into a prime (30204021119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2157430073 + ... + 2157430086.
It is an arithmetic number, because the mean of its divisors is an integer number (8629720320).
Almost surely, 230204021113 is an apocalyptic number.
It is an amenable number.
30204021113 is a deficient number, since it is larger than the sum of its proper divisors (4314860167).
30204021113 is an equidigital number, since it uses as much as digits as its factorization.
30204021113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4314860166.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 30204021113 its reverse (31112040203), we get a palindrome (61316061316).
The spelling of 30204021113 in words is "thirty billion, two hundred four million, twenty-one thousand, one hundred thirteen".
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