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30213120341143 = 117125801127533
BaseRepresentation
bin1101101111010100010100…
…10011100011010010010111
310221222100100022012211110101
412313222022103203102113
512430002432301404033
6144131414343434531
76235553200402525
oct667521223432227
9127870308184411
1030213120341143
1196993488617a3
12347b608a55a47
1313b2114a4639c
14766473ba1315
15375da502197d
hex1b7a8a4e3497

30213120341143 has 4 divisors (see below), whose sum is σ = 30238921469848. Its totient is φ = 30187319212440.

The previous prime is 30213120341141. The next prime is 30213120341233. The reversal of 30213120341143 is 34114302131203.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 30213120341143 - 21 = 30213120341141 is a prime.

It is a super-3 number, since 3×302131203411433 (a number of 41 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (30213120341141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12900562596 + ... + 12900564937.

It is an arithmetic number, because the mean of its divisors is an integer number (7559730367462).

Almost surely, 230213120341143 is an apocalyptic number.

30213120341143 is a deficient number, since it is larger than the sum of its proper divisors (25801128705).

30213120341143 is a wasteful number, since it uses less digits than its factorization.

30213120341143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25801128704.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 30213120341143 its reverse (34114302131203), we get a palindrome (64327422472346).

The spelling of 30213120341143 in words is "thirty trillion, two hundred thirteen billion, one hundred twenty million, three hundred forty-one thousand, one hundred forty-three".

Divisors: 1 1171 25801127533 30213120341143