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302132113121 = 614952985461
BaseRepresentation
bin1000110010110000111…
…10100010111011100001
31001212212002212121002202
410121120132202323201
514422231310104441
6350444135422545
730554054405516
oct4313036427341
91055762777082
10302132113121
11107151779463
124a67b524a55
132264c7814c7
14108a238b30d
157cd496b19b
hex46587a2ee1

302132113121 has 4 divisors (see below), whose sum is σ = 307085098644. Its totient is φ = 297179127600.

The previous prime is 302132113117. The next prime is 302132113133. The reversal of 302132113121 is 121311231203.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 121311231203 = 169771485699.

It can be written as a sum of positive squares in 2 ways, for example, as 10072932496 + 292059180625 = 100364^2 + 540425^2 .

It is a cyclic number.

It is not a de Polignac number, because 302132113121 - 22 = 302132113117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 302132113093 and 302132113102.

It is not an unprimeable number, because it can be changed into a prime (302132113321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2476492670 + ... + 2476492791.

It is an arithmetic number, because the mean of its divisors is an integer number (76771274661).

Almost surely, 2302132113121 is an apocalyptic number.

It is an amenable number.

302132113121 is a deficient number, since it is larger than the sum of its proper divisors (4952985523).

302132113121 is an equidigital number, since it uses as much as digits as its factorization.

302132113121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4952985522.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 302132113121 its reverse (121311231203), we get a palindrome (423443344324).

The spelling of 302132113121 in words is "three hundred two billion, one hundred thirty-two million, one hundred thirteen thousand, one hundred twenty-one".

Divisors: 1 61 4952985461 302132113121