Base | Representation |
---|---|
bin | 1101110000001000011101… |
… | …10000011100000101110011 |
3 | 10222002000121010001012010112 |
4 | 12320010032300130011303 |
5 | 12430432244222411011 |
6 | 144152324124451535 |
7 | 6240563645250542 |
oct | 670041660340563 |
9 | 128060533035115 |
10 | 30241112310131 |
11 | 96aa202573368 |
12 | 3484b1b3a9bab |
13 | 13b49560b1848 |
14 | 76796b660159 |
15 | 3769926ed58b |
hex | 1b810ec1c173 |
30241112310131 has 2 divisors, whose sum is σ = 30241112310132. Its totient is φ = 30241112310130.
The previous prime is 30241112310011. The next prime is 30241112310137. The reversal of 30241112310131 is 13101321114203.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30241112310131 is a prime.
It is a super-2 number, since 2×302411123101312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 30241112310097 and 30241112310106.
It is not a weakly prime, because it can be changed into another prime (30241112310137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15120556155065 + 15120556155066.
It is an arithmetic number, because the mean of its divisors is an integer number (15120556155066).
Almost surely, 230241112310131 is an apocalyptic number.
30241112310131 is a deficient number, since it is larger than the sum of its proper divisors (1).
30241112310131 is an equidigital number, since it uses as much as digits as its factorization.
30241112310131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 30241112310131 its reverse (13101321114203), we get a palindrome (43342433424334).
The spelling of 30241112310131 in words is "thirty trillion, two hundred forty-one billion, one hundred twelve million, three hundred ten thousand, one hundred thirty-one".
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