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303130000153 is a prime number
BaseRepresentation
bin1000110100100111111…
…01001011101100011001
31001222102122120111202201
410122103331023230121
514431302240001103
6351131143530201
730620562326251
oct4322375135431
91058378514681
10303130000153
11107613a89792
124a8b9759961
132277b42b9c6
1410958b08961
157d4238151d
hex4693f4bb19

303130000153 has 2 divisors, whose sum is σ = 303130000154. Its totient is φ = 303130000152.

The previous prime is 303130000099. The next prime is 303130000157. The reversal of 303130000153 is 351000031303.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 267483427344 + 35646572809 = 517188^2 + 188803^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-303130000153 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 303130000153.

It is not a weakly prime, because it can be changed into another prime (303130000157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 151565000076 + 151565000077.

It is an arithmetic number, because the mean of its divisors is an integer number (151565000077).

Almost surely, 2303130000153 is an apocalyptic number.

It is an amenable number.

303130000153 is a deficient number, since it is larger than the sum of its proper divisors (1).

303130000153 is an equidigital number, since it uses as much as digits as its factorization.

303130000153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 405, while the sum is 19.

Adding to 303130000153 its reverse (351000031303), we get a palindrome (654130031456).

The spelling of 303130000153 in words is "three hundred three billion, one hundred thirty million, one hundred fifty-three", and thus it is an aban number.