Base | Representation |
---|---|
bin | 101100000111110011111… |
… | …010000000001101111011 |
3 | 101201212020100201202201121 |
4 | 230013303322000031323 |
5 | 344134111231344121 |
6 | 10240522441530111 |
7 | 432025606603561 |
oct | 54076372001573 |
9 | 11655210652647 |
10 | 3032044012411 |
11 | a69978888567 |
12 | 40b7694a3937 |
13 | 18cbc750c2ab |
14 | a6a749b5a31 |
15 | 53d0ca26141 |
hex | 2c1f3e8037b |
3032044012411 has 2 divisors, whose sum is σ = 3032044012412. Its totient is φ = 3032044012410.
The previous prime is 3032044012369. The next prime is 3032044012453. The reversal of 3032044012411 is 1142104402303.
3032044012411 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (3032044012369) and next prime (3032044012453).
It is a cyclic number.
It is not a de Polignac number, because 3032044012411 - 213 = 3032044004219 is a prime.
It is not a weakly prime, because it can be changed into another prime (3032044012511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1516022006205 + 1516022006206.
It is an arithmetic number, because the mean of its divisors is an integer number (1516022006206).
Almost surely, 23032044012411 is an apocalyptic number.
3032044012411 is a deficient number, since it is larger than the sum of its proper divisors (1).
3032044012411 is an equidigital number, since it uses as much as digits as its factorization.
3032044012411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 3032044012411 its reverse (1142104402303), we get a palindrome (4174148414714).
The spelling of 3032044012411 in words is "three trillion, thirty-two billion, forty-four million, twelve thousand, four hundred eleven".
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