303303000113 has 4 divisors (see below), whose sum is σ = 303582028800. Its totient is φ = 303023971428.

The previous prime is 303303000061. The next prime is 303303000127. The reversal of 303303000113 is 311000303303.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 303303000113 - 2¹⁶ = 303302934577 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 303303000091 and 303303000100.

It is not an unprimeable number, because it can be changed into a prime (303303000163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139512713 + ... + 139514886.

It is an arithmetic number, because the mean of its divisors is an integer number (75895507200).

Almost surely, 2^303303000113 is an apocalyptic number.

It is an amenable number.

303303000113 is a deficient number, since it is larger than the sum of its proper divisors (279028687).

303303000113 is a wasteful number, since it uses less digits than its factorization.

303303000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 279028686.

The product of its (nonzero) digits is 243, while the sum is 17.

Adding to 303303000113 its reverse (311000303303), we get a palindrome (614303303416).

The spelling of 303303000113 in words is "three hundred three billion, three hundred three million, one hundred thirteen", and thus it is an aban number.