Base | Representation |
---|---|
bin | 1011010011001011… |
… | …0010110010100101 |
3 | 21211101112020112121 |
4 | 2310302302302211 |
5 | 22203000322432 |
6 | 1220552145541 |
7 | 135110615563 |
oct | 26462626245 |
9 | 7741466477 |
10 | 3033214117 |
11 | 131719672a |
12 | 7079982b1 |
13 | 39454346b |
14 | 20abb0a33 |
15 | 12b455197 |
hex | b4cb2ca5 |
3033214117 has 2 divisors, whose sum is σ = 3033214118. Its totient is φ = 3033214116.
The previous prime is 3033214091. The next prime is 3033214133. The reversal of 3033214117 is 7114123303.
3033214117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2414149956 + 619064161 = 49134^2 + 24881^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3033214117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3033214091 and 3033214100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3033214417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1516607058 + 1516607059.
It is an arithmetic number, because the mean of its divisors is an integer number (1516607059).
Almost surely, 23033214117 is an apocalyptic number.
It is an amenable number.
3033214117 is a deficient number, since it is larger than the sum of its proper divisors (1).
3033214117 is an equidigital number, since it uses as much as digits as its factorization.
3033214117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
The square root of 3033214117 is about 55074.6231671175. The cubic root of 3033214117 is about 1447.5526082202.
The spelling of 3033214117 in words is "three billion, thirty-three million, two hundred fourteen thousand, one hundred seventeen".
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