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30342414433 is a prime number
BaseRepresentation
bin11100010000100011…
…001000000001100001
32220022121121100200011
4130100203020001201
5444120124230213
621534503124521
72122625160442
oct342043100141
986277540604
1030342414433
1111960558071
125a69743741
132b272c36a6
14167badd2c9
15bc8c1503d
hex7108c8061

30342414433 has 2 divisors, whose sum is σ = 30342414434. Its totient is φ = 30342414432.

The previous prime is 30342414409. The next prime is 30342414503. The reversal of 30342414433 is 33441424303.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23649211089 + 6693203344 = 153783^2 + 81812^2 .

It is a cyclic number.

It is not a de Polignac number, because 30342414433 - 29 = 30342413921 is a prime.

It is a super-2 number, since 2×303424144332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 30342414395 and 30342414404.

It is not a weakly prime, because it can be changed into another prime (30342414233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15171207216 + 15171207217.

It is an arithmetic number, because the mean of its divisors is an integer number (15171207217).

Almost surely, 230342414433 is an apocalyptic number.

It is an amenable number.

30342414433 is a deficient number, since it is larger than the sum of its proper divisors (1).

30342414433 is an equidigital number, since it uses as much as digits as its factorization.

30342414433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 30342414433 its reverse (33441424303), we get a palindrome (63783838736).

The spelling of 30342414433 in words is "thirty billion, three hundred forty-two million, four hundred fourteen thousand, four hundred thirty-three".