Base | Representation |
---|---|
bin | 101100001111010110100… |
… | …010011010100001001011 |
3 | 101202122010200001201212112 |
4 | 230033112202122201023 |
5 | 344302202123132021 |
6 | 10244342133132535 |
7 | 432433351013513 |
oct | 54172642324113 |
9 | 11678120051775 |
10 | 3040141224011 |
11 | a72353512481 |
12 | 41124918a14b |
13 | 1908b7c2a968 |
14 | a7202146843 |
15 | 54133824d5b |
hex | 2c3d689a84b |
3040141224011 has 2 divisors, whose sum is σ = 3040141224012. Its totient is φ = 3040141224010.
The previous prime is 3040141223953. The next prime is 3040141224041. The reversal of 3040141224011 is 1104221410403.
3040141224011 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3040141224011 is a prime.
It is a super-2 number, since 2×30401412240112 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3040141224041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1520070612005 + 1520070612006.
It is an arithmetic number, because the mean of its divisors is an integer number (1520070612006).
Almost surely, 23040141224011 is an apocalyptic number.
3040141224011 is a deficient number, since it is larger than the sum of its proper divisors (1).
3040141224011 is an equidigital number, since it uses as much as digits as its factorization.
3040141224011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 3040141224011 its reverse (1104221410403), we get a palindrome (4144362634414).
The spelling of 3040141224011 in words is "three trillion, forty billion, one hundred forty-one million, two hundred twenty-four thousand, eleven".
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