Search a number
-
+
304039974853 is a prime number
BaseRepresentation
bin1000110110010100011…
…00011101011111000101
31002001210001212000101101
410123022030131133011
514440133213143403
6351401331500101
730652252100566
oct4331214353705
91061701760341
10304039974853
11107a4070419a
124ab12457631
1322894b08584
1410a0390016d
157d971cd71d
hex46ca31d7c5

304039974853 has 2 divisors, whose sum is σ = 304039974854. Its totient is φ = 304039974852.

The previous prime is 304039974779. The next prime is 304039974869. The reversal of 304039974853 is 358479930403.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 303979103649 + 60871204 = 551343^2 + 7802^2 .

It is a cyclic number.

It is not a de Polignac number, because 304039974853 - 237 = 166601021381 is a prime.

It is a super-2 number, since 2×3040399748532 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 304039974794 and 304039974803.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (304039974893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 152019987426 + 152019987427.

It is an arithmetic number, because the mean of its divisors is an integer number (152019987427).

Almost surely, 2304039974853 is an apocalyptic number.

It is an amenable number.

304039974853 is a deficient number, since it is larger than the sum of its proper divisors (1).

304039974853 is an equidigital number, since it uses as much as digits as its factorization.

304039974853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9797760, while the sum is 55.

The spelling of 304039974853 in words is "three hundred four billion, thirty-nine million, nine hundred seventy-four thousand, eight hundred fifty-three".