Base | Representation |
---|---|
bin | 100010100100010001010011… |
… | …0010100001111001001100111 |
3 | 1110212120002122200110202200221 |
4 | 1011020202212110033021213 |
5 | 304323042212434004343 |
6 | 2554355340254345211 |
7 | 121021016600044351 |
oct | 10510424624171147 |
9 | 1425502580422627 |
10 | 304052115141223 |
11 | 88975861414039 |
12 | 2a1274061bb207 |
13 | 10086cb722cb07 |
14 | 55122b53740d1 |
15 | 252415ec175ed |
hex | 11488a650f267 |
304052115141223 has 16 divisors (see below), whose sum is σ = 323023970304000. Its totient is φ = 285201985908096.
The previous prime is 304052115141197. The next prime is 304052115141301. The reversal of 304052115141223 is 322141511250403.
It is a cyclic number.
It is not a de Polignac number, because 304052115141223 - 217 = 304052115010151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (304052115171223) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6165223 + ... + 25418776.
It is an arithmetic number, because the mean of its divisors is an integer number (20188998144000).
Almost surely, 2304052115141223 is an apocalyptic number.
304052115141223 is a deficient number, since it is larger than the sum of its proper divisors (18971855162777).
304052115141223 is a wasteful number, since it uses less digits than its factorization.
304052115141223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31585926.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 304052115141223 its reverse (322141511250403), we get a palindrome (626193626391626).
The spelling of 304052115141223 in words is "three hundred four trillion, fifty-two billion, one hundred fifteen million, one hundred forty-one thousand, two hundred twenty-three".
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