Base | Representation |
---|---|
bin | 101100010000010110010… |
… | …111101001011000010111 |
3 | 101202201220022012001201111 |
4 | 230100112113221120113 |
5 | 344311400302040002 |
6 | 10245040310435451 |
7 | 432502033456624 |
oct | 54202627513027 |
9 | 11681808161644 |
10 | 3041212143127 |
11 | a72852a748a4 |
12 | 4114a7962b87 |
13 | 190a28a68b02 |
14 | a72a447534b |
15 | 541978643d7 |
hex | 2c4165e9617 |
3041212143127 has 2 divisors, whose sum is σ = 3041212143128. Its totient is φ = 3041212143126.
The previous prime is 3041212143107. The next prime is 3041212143169. The reversal of 3041212143127 is 7213412121403.
3041212143127 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (7213412121403) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3041212143127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3041212143107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1520606071563 + 1520606071564.
It is an arithmetic number, because the mean of its divisors is an integer number (1520606071564).
Almost surely, 23041212143127 is an apocalyptic number.
3041212143127 is a deficient number, since it is larger than the sum of its proper divisors (1).
3041212143127 is an equidigital number, since it uses as much as digits as its factorization.
3041212143127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
The spelling of 3041212143127 in words is "three trillion, forty-one billion, two hundred twelve million, one hundred forty-three thousand, one hundred twenty-seven".
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