Base | Representation |
---|---|
bin | 1101110101000111000000… |
… | …10010100111001110000111 |
3 | 10222200101000201200200200102 |
4 | 12322203200102213032013 |
5 | 12441233021121300203 |
6 | 144403050150034315 |
7 | 6256126652635466 |
oct | 672434022471607 |
9 | 128611021620612 |
10 | 30412131431303 |
11 | 9765792394336 |
12 | 34b20a934899b |
13 | 13c7b0c20c1bb |
14 | 771d527c09dd |
15 | 37b151755888 |
hex | 1ba8e04a7387 |
30412131431303 has 4 divisors (see below), whose sum is σ = 30420200453760. Its totient is φ = 30404062408848.
The previous prime is 30412131431263. The next prime is 30412131431317. The reversal of 30412131431303 is 30313413121403.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 30412131431303 - 240 = 29312619803527 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30412131431203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4034505575 + ... + 4034513112.
It is an arithmetic number, because the mean of its divisors is an integer number (7605050113440).
Almost surely, 230412131431303 is an apocalyptic number.
30412131431303 is a deficient number, since it is larger than the sum of its proper divisors (8069022457).
30412131431303 is an equidigital number, since it uses as much as digits as its factorization.
30412131431303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8069022456.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 30412131431303 its reverse (30313413121403), we get a palindrome (60725544552706).
The spelling of 30412131431303 in words is "thirty trillion, four hundred twelve billion, one hundred thirty-one million, four hundred thirty-one thousand, three hundred three".
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