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304140113 = 428371011
BaseRepresentation
bin10010001000001…
…100111101010001
3210012021220210122
4102020030331101
51110324440423
650102440025
710352101604
oct2210147521
9705256718
10304140113
11146751a72
1285a33015
134b01a384
142c57033b
151ba7a8c8
hex1220cf51

304140113 has 4 divisors (see below), whose sum is σ = 304215408. Its totient is φ = 304064820.

The previous prime is 304140071. The next prime is 304140131. The reversal of 304140113 is 311041403.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 304140113 - 228 = 35704657 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 304140091 and 304140100.

It is not an unprimeable number, because it can be changed into a prime (304140143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31223 + ... + 39788.

It is an arithmetic number, because the mean of its divisors is an integer number (76053852).

Almost surely, 2304140113 is an apocalyptic number.

It is an amenable number.

304140113 is a deficient number, since it is larger than the sum of its proper divisors (75295).

304140113 is an equidigital number, since it uses as much as digits as its factorization.

304140113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75294.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 304140113 is about 17439.6133271354. The cubic root of 304140113 is about 672.4983673486.

Adding to 304140113 its reverse (311041403), we get a palindrome (615181516).

The spelling of 304140113 in words is "three hundred four million, one hundred forty thousand, one hundred thirteen".

Divisors: 1 4283 71011 304140113