Base | Representation |
---|---|
bin | 1101110101011011010101… |
… | …01100100001000010010101 |
3 | 10222201102012012111202021222 |
4 | 12322231222230201002111 |
5 | 12441422343103141432 |
6 | 144412053031420125 |
7 | 6256664243145566 |
oct | 672555254410225 |
9 | 128642165452258 |
10 | 30423043412117 |
11 | 976a381973aa4 |
12 | 34b4233824645 |
13 | 13c8b5ab29395 |
14 | 7726a9adc16d |
15 | 37b58e70a112 |
hex | 1bab6ab21095 |
30423043412117 has 2 divisors, whose sum is σ = 30423043412118. Its totient is φ = 30423043412116.
The previous prime is 30423043412087. The next prime is 30423043412131. The reversal of 30423043412117 is 71121434032403.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27328209514321 + 3094833897796 = 5227639^2 + 1759214^2 .
It is an emirp because it is prime and its reverse (71121434032403) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 30423043412117 - 234 = 30405863542933 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30423043412617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15211521706058 + 15211521706059.
It is an arithmetic number, because the mean of its divisors is an integer number (15211521706059).
Almost surely, 230423043412117 is an apocalyptic number.
It is an amenable number.
30423043412117 is a deficient number, since it is larger than the sum of its proper divisors (1).
30423043412117 is an equidigital number, since it uses as much as digits as its factorization.
30423043412117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
The spelling of 30423043412117 in words is "thirty trillion, four hundred twenty-three billion, forty-three million, four hundred twelve thousand, one hundred seventeen".
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