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30424102117 is a prime number
BaseRepresentation
bin11100010101011010…
…101111010011100101
32220112022022112002221
4130111122233103211
5444302032231432
621550542032341
72124636413113
oct342532572345
986468275087
1030424102117
11119a2681252
125a90b786b1
132b3b1c4cb6
1416888c4ab3
15bd0e9db97
hex7156af4e5

30424102117 has 2 divisors, whose sum is σ = 30424102118. Its totient is φ = 30424102116.

The previous prime is 30424102067. The next prime is 30424102123. The reversal of 30424102117 is 71120142403.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23576374116 + 6847728001 = 153546^2 + 82751^2 .

It is an emirp because it is prime and its reverse (71120142403) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 30424102117 - 219 = 30423577829 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 30424102091 and 30424102100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (30424102417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15212051058 + 15212051059.

It is an arithmetic number, because the mean of its divisors is an integer number (15212051059).

Almost surely, 230424102117 is an apocalyptic number.

It is an amenable number.

30424102117 is a deficient number, since it is larger than the sum of its proper divisors (1).

30424102117 is an equidigital number, since it uses as much as digits as its factorization.

30424102117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 25.

The spelling of 30424102117 in words is "thirty billion, four hundred twenty-four million, one hundred two thousand, one hundred seventeen".