Base | Representation |
---|---|
bin | 1011010111011100… |
… | …1001110010100001 |
3 | 21212122020200011011 |
4 | 2311313021302201 |
5 | 22222042242423 |
6 | 1222432220521 |
7 | 135416132506 |
oct | 26567116241 |
9 | 7778220134 |
10 | 3051134113 |
11 | 1326316245 |
12 | 71199a741 |
13 | 398178c01 |
14 | 20d3174ad |
15 | 12cce4b0d |
hex | b5dc9ca1 |
3051134113 has 2 divisors, whose sum is σ = 3051134114. Its totient is φ = 3051134112.
The previous prime is 3051134081. The next prime is 3051134189. The reversal of 3051134113 is 3114311503.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2577288289 + 473845824 = 50767^2 + 21768^2 .
It is a cyclic number.
It is not a de Polignac number, because 3051134113 - 25 = 3051134081 is a prime.
It is not a weakly prime, because it can be changed into another prime (3051234113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1525567056 + 1525567057.
It is an arithmetic number, because the mean of its divisors is an integer number (1525567057).
Almost surely, 23051134113 is an apocalyptic number.
It is an amenable number.
3051134113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3051134113 is an equidigital number, since it uses as much as digits as its factorization.
3051134113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
The square root of 3051134113 is about 55237.0719082755. The cubic root of 3051134113 is about 1450.3976892517.
Adding to 3051134113 its reverse (3114311503), we get a palindrome (6165445616).
The spelling of 3051134113 in words is "three billion, fifty-one million, one hundred thirty-four thousand, one hundred thirteen".
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