Base | Representation |
---|---|
bin | 1101111000100010100111… |
… | …10110110011001001010011 |
3 | 11000002122100120221210110101 |
4 | 12330101103312303021103 |
5 | 13000201002302223123 |
6 | 144533145412113231 |
7 | 6300502466516344 |
oct | 674212366631123 |
9 | 130078316853411 |
10 | 30530034414163 |
11 | 9800795568439 |
12 | 3510b12905817 |
13 | 1405c7bb1130b |
14 | 7779394160cb |
15 | 37e252582aad |
hex | 1bc453db3253 |
30530034414163 has 2 divisors, whose sum is σ = 30530034414164. Its totient is φ = 30530034414162.
The previous prime is 30530034414161. The next prime is 30530034414179. The reversal of 30530034414163 is 36141443003503.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 30530034414163 - 21 = 30530034414161 is a prime.
It is a super-2 number, since 2×305300344141632 (a number of 28 digits) contains 22 as substring.
Together with 30530034414161, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (30530034414161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15265017207081 + 15265017207082.
It is an arithmetic number, because the mean of its divisors is an integer number (15265017207082).
Almost surely, 230530034414163 is an apocalyptic number.
30530034414163 is a deficient number, since it is larger than the sum of its proper divisors (1).
30530034414163 is an equidigital number, since it uses as much as digits as its factorization.
30530034414163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 37.
Adding to 30530034414163 its reverse (36141443003503), we get a palindrome (66671477417666).
The spelling of 30530034414163 in words is "thirty trillion, five hundred thirty billion, thirty-four million, four hundred fourteen thousand, one hundred sixty-three".
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