Base | Representation |
---|---|
bin | 1101111000101010001111… |
… | …00101101000010011110011 |
3 | 11000010000220120101121211021 |
4 | 12330111013211220103303 |
5 | 13000232341112212120 |
6 | 144535103244400311 |
7 | 6301006021604053 |
oct | 674250745502363 |
9 | 130100816347737 |
10 | 30534123554035 |
11 | 98024a37a5782 |
12 | 3511874246097 |
13 | 14064810432ca |
14 | 777c06531563 |
15 | 37e3e1564aaa |
hex | 1bc5479684f3 |
30534123554035 has 8 divisors (see below), whose sum is σ = 37261981286640. Its totient is φ = 24013276828704.
The previous prime is 30534123554009. The next prime is 30534123554057. The reversal of 30534123554035 is 53045532143503.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 30534123554035 - 215 = 30534123521267 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 30534123553982 and 30534123554000.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51752751492 + ... + 51752752081.
It is an arithmetic number, because the mean of its divisors is an integer number (4657747660830).
Almost surely, 230534123554035 is an apocalyptic number.
30534123554035 is a deficient number, since it is larger than the sum of its proper divisors (6727857732605).
30534123554035 is a wasteful number, since it uses less digits than its factorization.
30534123554035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103505503637.
The product of its (nonzero) digits is 1620000, while the sum is 43.
Adding to 30534123554035 its reverse (53045532143503), we get a palindrome (83579655697538).
The spelling of 30534123554035 in words is "thirty trillion, five hundred thirty-four billion, one hundred twenty-three million, five hundred fifty-four thousand, thirty-five".
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