Base | Representation |
---|---|
bin | 101100011011101110001… |
… | …101101101001011001001 |
3 | 101210220102022201200002020 |
4 | 230123232031231023021 |
5 | 400011402334203343 |
6 | 10254420123155053 |
7 | 433413451146336 |
oct | 54335615551311 |
9 | 11726368650066 |
10 | 3053423350473 |
11 | a77a499736a1 |
12 | 413935375a89 |
13 | 191c238acba2 |
14 | a7b0215198d |
15 | 5465e904b83 |
hex | 2c6ee36d2c9 |
3053423350473 has 8 divisors (see below), whose sum is σ = 4122765705600. Its totient is φ = 2009848281168.
The previous prime is 3053423350457. The next prime is 3053423350511. The reversal of 3053423350473 is 3740533243503.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3053423350473 - 24 = 3053423350457 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3053423350973) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6441821178 + ... + 6441821651.
It is an arithmetic number, because the mean of its divisors is an integer number (515345713200).
Almost surely, 23053423350473 is an apocalyptic number.
It is an amenable number.
3053423350473 is a deficient number, since it is larger than the sum of its proper divisors (1069342355127).
3053423350473 is a wasteful number, since it uses less digits than its factorization.
3053423350473 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12883642911.
The product of its (nonzero) digits is 1360800, while the sum is 42.
Adding to 3053423350473 its reverse (3740533243503), we get a palindrome (6793956593976).
The spelling of 3053423350473 in words is "three trillion, fifty-three billion, four hundred twenty-three million, three hundred fifty thousand, four hundred seventy-three".
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