Base | Representation |
---|---|
bin | 101100011011110011000… |
… | …100001111110101010001 |
3 | 101210220121222220112221111 |
4 | 230123303010033311101 |
5 | 400012034204211243 |
6 | 10254432152053321 |
7 | 433415460121351 |
oct | 54336304176521 |
9 | 11726558815844 |
10 | 3053504757073 |
11 | a77a90915681 |
12 | 413958694241 |
13 | 191c37713584 |
14 | a7b0cca2b61 |
15 | 54666b3539d |
hex | 2c6f310fd51 |
3053504757073 has 2 divisors, whose sum is σ = 3053504757074. Its totient is φ = 3053504757072.
The previous prime is 3053504757071. The next prime is 3053504757119. The reversal of 3053504757073 is 3707574053503.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3012335129664 + 41169627409 = 1735608^2 + 202903^2 .
It is a cyclic number.
It is not a de Polignac number, because 3053504757073 - 21 = 3053504757071 is a prime.
Together with 3053504757071, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3053504757071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526752378536 + 1526752378537.
It is an arithmetic number, because the mean of its divisors is an integer number (1526752378537).
Almost surely, 23053504757073 is an apocalyptic number.
It is an amenable number.
3053504757073 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053504757073 is an equidigital number, since it uses as much as digits as its factorization.
3053504757073 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4630500, while the sum is 49.
The spelling of 3053504757073 in words is "three trillion, fifty-three billion, five hundred four million, seven hundred fifty-seven thousand, seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •