Base | Representation |
---|---|
bin | 101100011011110100110… |
… | …100111110000010001011 |
3 | 101210220201001111211001121 |
4 | 230123310310332002023 |
5 | 400012114240301233 |
6 | 10254435125300111 |
7 | 433416266232205 |
oct | 54336464760213 |
9 | 11726631454047 |
10 | 3053534306443 |
11 | a77aa6568545 |
12 | 413966564637 |
13 | 191c4088b3ca |
14 | a7b12b95775 |
15 | 5466952092d |
hex | 2c6f4d3e08b |
3053534306443 has 2 divisors, whose sum is σ = 3053534306444. Its totient is φ = 3053534306442.
The previous prime is 3053534306437. The next prime is 3053534306507. The reversal of 3053534306443 is 3446034353503.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3053534306443 - 217 = 3053534175371 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3053534306443.
It is not a weakly prime, because it can be changed into another prime (3053534306143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526767153221 + 1526767153222.
It is an arithmetic number, because the mean of its divisors is an integer number (1526767153222).
Almost surely, 23053534306443 is an apocalyptic number.
3053534306443 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053534306443 is an equidigital number, since it uses as much as digits as its factorization.
3053534306443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2332800, while the sum is 43.
Adding to 3053534306443 its reverse (3446034353503), we get a palindrome (6499568659946).
The spelling of 3053534306443 in words is "three trillion, fifty-three billion, five hundred thirty-four million, three hundred six thousand, four hundred forty-three".
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