Base | Representation |
---|---|
bin | 101100011011110100110… |
… | …100111101111101011111 |
3 | 101210220201001111210122111 |
4 | 230123310310331331133 |
5 | 400012114240244033 |
6 | 10254435125254451 |
7 | 433416266231266 |
oct | 54336464757537 |
9 | 11726631453574 |
10 | 3053534306143 |
11 | a77aa65682a2 |
12 | 413966564427 |
13 | 191c4088b229 |
14 | a7b12b955dd |
15 | 546695207cd |
hex | 2c6f4d3df5f |
3053534306143 has 2 divisors, whose sum is σ = 3053534306144. Its totient is φ = 3053534306142.
The previous prime is 3053534306129. The next prime is 3053534306159. The reversal of 3053534306143 is 3416034353503.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3053534306143 - 229 = 3052997435231 is a prime.
It is a super-3 number, since 3×30535343061433 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3053534306096 and 3053534306105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3053534306443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526767153071 + 1526767153072.
It is an arithmetic number, because the mean of its divisors is an integer number (1526767153072).
Almost surely, 23053534306143 is an apocalyptic number.
3053534306143 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053534306143 is an equidigital number, since it uses as much as digits as its factorization.
3053534306143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 583200, while the sum is 40.
Adding to 3053534306143 its reverse (3416034353503), we get a palindrome (6469568659646).
The spelling of 3053534306143 in words is "three trillion, fifty-three billion, five hundred thirty-four million, three hundred six thousand, one hundred forty-three".
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