Base | Representation |
---|---|
bin | 1101111000110101100110… |
… | …01001101010111101100011 |
3 | 11000010121122122211021002102 |
4 | 12330122303021222331203 |
5 | 13000332334110201431 |
6 | 144541552415441015 |
7 | 6301313125264523 |
oct | 674326311527543 |
9 | 130117578737072 |
10 | 30540223131491 |
11 | 9805043859587 |
12 | 3512a96b2616b |
13 | 1406c13935438 |
14 | 778224661683 |
15 | 37e64bcbbdcb |
hex | 1bc6b326af63 |
30540223131491 has 2 divisors, whose sum is σ = 30540223131492. Its totient is φ = 30540223131490.
The previous prime is 30540223131389. The next prime is 30540223131499. The reversal of 30540223131491 is 19413132204503.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30540223131491 is a prime.
It is not a weakly prime, because it can be changed into another prime (30540223131499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15270111565745 + 15270111565746.
It is an arithmetic number, because the mean of its divisors is an integer number (15270111565746).
Almost surely, 230540223131491 is an apocalyptic number.
30540223131491 is a deficient number, since it is larger than the sum of its proper divisors (1).
30540223131491 is an equidigital number, since it uses as much as digits as its factorization.
30540223131491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 38.
Adding to 30540223131491 its reverse (19413132204503), we get a palindrome (49953355335994).
The spelling of 30540223131491 in words is "thirty trillion, five hundred forty billion, two hundred twenty-three million, one hundred thirty-one thousand, four hundred ninety-one".
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