Base | Representation |
---|---|
bin | 101100011100010011011… |
… | …110000110010000010111 |
3 | 101210222000212212201000111 |
4 | 230130103132012100113 |
5 | 400014142342421003 |
6 | 10255002132223451 |
7 | 433435111054315 |
oct | 54342336062027 |
9 | 11728025781014 |
10 | 3054048404503 |
11 | a7823a783a78 |
12 | 413a8a76ab87 |
13 | 191cc323b445 |
14 | a7b6117b0b5 |
15 | 54699720e6d |
hex | 2c713786417 |
3054048404503 has 4 divisors (see below), whose sum is σ = 3081075381648. Its totient is φ = 3027021427360.
The previous prime is 3054048404467. The next prime is 3054048404549.
3054048404503 is nontrivially palindromic in base 10.
3054048404503 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3054048404503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3054048404203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13513488403 + ... + 13513488628.
It is an arithmetic number, because the mean of its divisors is an integer number (770268845412).
Almost surely, 23054048404503 is an apocalyptic number.
3054048404503 is a deficient number, since it is larger than the sum of its proper divisors (27026977145).
3054048404503 is a wasteful number, since it uses less digits than its factorization.
3054048404503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27026977144.
The product of its (nonzero) digits is 460800, while the sum is 40.
The spelling of 3054048404503 in words is "three trillion, fifty-four billion, forty-eight million, four hundred four thousand, five hundred three".
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