Base | Representation |
---|---|
bin | 1101111000111000000000… |
… | …00011110110001001110111 |
3 | 11000010201222120210020110122 |
4 | 12330130000003312021313 |
5 | 13000343004420400403 |
6 | 144542324431442155 |
7 | 6301360113643415 |
oct | 674340003661167 |
9 | 130121876706418 |
10 | 30541513450103 |
11 | 9805646143aa7 |
12 | 351319708635b |
13 | 140708b060886 |
14 | 778307b822b5 |
15 | 37e6c51e8838 |
hex | 1bc7000f6277 |
30541513450103 has 4 divisors (see below), whose sum is σ = 30544812747840. Its totient is φ = 30538214152368.
The previous prime is 30541513450069. The next prime is 30541513450139. The reversal of 30541513450103 is 30105431514503.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 30541513450103 - 26 = 30541513450039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30541513450153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1649634983 + ... + 1649653496.
It is an arithmetic number, because the mean of its divisors is an integer number (7636203186960).
Almost surely, 230541513450103 is an apocalyptic number.
30541513450103 is a deficient number, since it is larger than the sum of its proper divisors (3299297737).
30541513450103 is an equidigital number, since it uses as much as digits as its factorization.
30541513450103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3299297736.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 30541513450103 its reverse (30105431514503), we get a palindrome (60646944964606).
The spelling of 30541513450103 in words is "thirty trillion, five hundred forty-one billion, five hundred thirteen million, four hundred fifty thousand, one hundred three".
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