Base | Representation |
---|---|
bin | 101100011101001100101… |
… | …001101101011111000011 |
3 | 101211001111202001111202021 |
4 | 230131030221231133003 |
5 | 400023123441000313 |
6 | 10255241242302311 |
7 | 433500640263232 |
oct | 54351451553703 |
9 | 11731452044667 |
10 | 3055007750083 |
11 | a7869225a563 |
12 | 4140b7ab7997 |
13 | 192116c12c53 |
14 | a7c12744b19 |
15 | 54703a7178d |
hex | 2c74ca6d7c3 |
3055007750083 has 2 divisors, whose sum is σ = 3055007750084. Its totient is φ = 3055007750082.
The previous prime is 3055007750071. The next prime is 3055007750129. The reversal of 3055007750083 is 3800577005503.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3055007750083 is a prime.
It is not a weakly prime, because it can be changed into another prime (3055007750783) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1527503875041 + 1527503875042.
It is an arithmetic number, because the mean of its divisors is an integer number (1527503875042).
Almost surely, 23055007750083 is an apocalyptic number.
3055007750083 is a deficient number, since it is larger than the sum of its proper divisors (1).
3055007750083 is an equidigital number, since it uses as much as digits as its factorization.
3055007750083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 441000, while the sum is 43.
The spelling of 3055007750083 in words is "three trillion, fifty-five billion, seven million, seven hundred fifty thousand, eighty-three".
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