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3055012521437 is a prime number
BaseRepresentation
bin101100011101001100111…
…011111010010111011101
3101211001112002000220211002
4230131030323322113131
5400023131201141222
610255241532440045
7433501025655002
oct54351473722735
911731462026732
103055012521437
11a78694a19328
124140b9619025
13192117bc3936
14a7c132278a9
15547041b5392
hex2c74cefa5dd

3055012521437 has 2 divisors, whose sum is σ = 3055012521438. Its totient is φ = 3055012521436.

The previous prime is 3055012521401. The next prime is 3055012521479. The reversal of 3055012521437 is 7341252105503.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3047000660356 + 8011861081 = 1745566^2 + 89509^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3055012521437 is a prime.

It is a super-2 number, since 2×30550125214372 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3055012521437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3055012521137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1527506260718 + 1527506260719.

It is an arithmetic number, because the mean of its divisors is an integer number (1527506260719).

Almost surely, 23055012521437 is an apocalyptic number.

It is an amenable number.

3055012521437 is a deficient number, since it is larger than the sum of its proper divisors (1).

3055012521437 is an equidigital number, since it uses as much as digits as its factorization.

3055012521437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126000, while the sum is 38.

The spelling of 3055012521437 in words is "three trillion, fifty-five billion, twelve million, five hundred twenty-one thousand, four hundred thirty-seven".