Base | Representation |
---|---|
bin | 1101111001010001010110… |
… | …01100111011111111101111 |
3 | 11000012001002222222002202120 |
4 | 12330220223030323333233 |
5 | 13001103342232434003 |
6 | 144552455045324023 |
7 | 6302351261015361 |
oct | 674505314737757 |
9 | 130161088862676 |
10 | 30555122155503 |
11 | 9810399982870 |
12 | 3515954706613 |
13 | 140844958868a |
14 | 778c392bcd31 |
15 | 37ec1ecd7853 |
hex | 1bca2b33bfef |
30555122155503 has 32 divisors (see below), whose sum is σ = 44734615580160. Its totient is φ = 18397250912640.
The previous prime is 30555122155483. The next prime is 30555122155511.
30555122155503 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 30555122155503 - 217 = 30555122024431 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30555122155003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5501325 + ... + 9559017.
It is an arithmetic number, because the mean of its divisors is an integer number (1397956736880).
Almost surely, 230555122155503 is an apocalyptic number.
30555122155503 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
30555122155503 is a deficient number, since it is larger than the sum of its proper divisors (14179493424657).
30555122155503 is a wasteful number, since it uses less digits than its factorization.
30555122155503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4059199.
The product of its (nonzero) digits is 562500, while the sum is 42.
The spelling of 30555122155503 in words is "thirty trillion, five hundred fifty-five billion, one hundred twenty-two million, one hundred fifty-five thousand, five hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •