Base | Representation |
---|---|
bin | 101100100100110000000… |
… | …001100100010101001011 |
3 | 101211211102220210101012022 |
4 | 230210300001210111023 |
5 | 400141231023234441 |
6 | 10303102100235055 |
7 | 434205622204511 |
oct | 54446001442513 |
9 | 11754386711168 |
10 | 3063117399371 |
11 | a81073a0a057 |
12 | 41579b99ba8b |
13 | 192b0a0978b3 |
14 | a83817d24b1 |
15 | 54a2a9ca84b |
hex | 2c93006454b |
3063117399371 has 2 divisors, whose sum is σ = 3063117399372. Its totient is φ = 3063117399370.
The previous prime is 3063117399367. The next prime is 3063117399373. The reversal of 3063117399371 is 1739937113603.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3063117399371 - 22 = 3063117399367 is a prime.
It is a super-2 number, since 2×30631173993712 (a number of 26 digits) contains 22 as substring.
Together with 3063117399373, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3063117399373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1531558699685 + 1531558699686.
It is an arithmetic number, because the mean of its divisors is an integer number (1531558699686).
Almost surely, 23063117399371 is an apocalyptic number.
3063117399371 is a deficient number, since it is larger than the sum of its proper divisors (1).
3063117399371 is an equidigital number, since it uses as much as digits as its factorization.
3063117399371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1928934, while the sum is 53.
The spelling of 3063117399371 in words is "three trillion, sixty-three billion, one hundred seventeen million, three hundred ninety-nine thousand, three hundred seventy-one".
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