Base | Representation |
---|---|
bin | 101100110000010010110… |
… | …000100101101010100101 |
3 | 101220000102200010022201211 |
4 | 230300102300211222211 |
5 | 400342121343423023 |
6 | 10312512000551421 |
7 | 435125015544631 |
oct | 54602260455245 |
9 | 11800380108654 |
10 | 3075511311013 |
11 | a86353a58339 |
12 | 41807a622571 |
13 | 194033a1b71b |
14 | a8bd986bdc1 |
15 | 55003b0aa0d |
hex | 2cc12c25aa5 |
3075511311013 has 2 divisors, whose sum is σ = 3075511311014. Its totient is φ = 3075511311012.
The previous prime is 3075511311007. The next prime is 3075511311053. The reversal of 3075511311013 is 3101131155703.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1933996425124 + 1141514885889 = 1390682^2 + 1068417^2 .
It is a cyclic number.
It is not a de Polignac number, because 3075511311013 - 25 = 3075511310981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3075511311053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1537755655506 + 1537755655507.
It is an arithmetic number, because the mean of its divisors is an integer number (1537755655507).
Almost surely, 23075511311013 is an apocalyptic number.
It is an amenable number.
3075511311013 is a deficient number, since it is larger than the sum of its proper divisors (1).
3075511311013 is an equidigital number, since it uses as much as digits as its factorization.
3075511311013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4725, while the sum is 31.
Adding to 3075511311013 its reverse (3101131155703), we get a palindrome (6176642466716).
The spelling of 3075511311013 in words is "three trillion, seventy-five billion, five hundred eleven million, three hundred eleven thousand, thirteen".
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