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3091417967201 is a prime number
BaseRepresentation
bin101100111111000110110…
…111101010101001100001
3101221112111020022011220012
4230333012313222221201
5401122210444422301
610324102223454305
7436230135104564
oct54770667525141
911845436264805
103091417967201
11a92076938593
1241b179757395
1319569a351a15
14a98a82624db
1555635313ebb
hex2cfc6deaa61

3091417967201 has 2 divisors, whose sum is σ = 3091417967202. Its totient is φ = 3091417967200.

The previous prime is 3091417967179. The next prime is 3091417967203. The reversal of 3091417967201 is 1027697141903.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1971103681600 + 1120314285601 = 1403960^2 + 1058449^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3091417967201 is a prime.

It is a super-2 number, since 2×30914179672012 (a number of 26 digits) contains 22 as substring.

Together with 3091417967203, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3091417967201.

It is not a weakly prime, because it can be changed into another prime (3091417967203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1545708983600 + 1545708983601.

It is an arithmetic number, because the mean of its divisors is an integer number (1545708983601).

Almost surely, 23091417967201 is an apocalyptic number.

It is an amenable number.

3091417967201 is a deficient number, since it is larger than the sum of its proper divisors (1).

3091417967201 is an equidigital number, since it uses as much as digits as its factorization.

3091417967201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 571536, while the sum is 50.

The spelling of 3091417967201 in words is "three trillion, ninety-one billion, four hundred seventeen million, nine hundred sixty-seven thousand, two hundred one".