Base | Representation |
---|---|
bin | 101101000111001101100… |
… | …111110111011001011101 |
3 | 101222100221202222020010220 |
4 | 231013031213313121131 |
5 | 401243022011401341 |
6 | 10332102004151553 |
7 | 436655615263023 |
oct | 55071547673135 |
9 | 11870852866126 |
10 | 3100121200221 |
11 | a95832663351 |
12 | 4209a83985b9 |
13 | 196456496946 |
14 | aa0920a6713 |
15 | 5599441ea66 |
hex | 2d1cd9f765d |
3100121200221 has 4 divisors (see below), whose sum is σ = 4133494933632. Its totient is φ = 2066747466812.
The previous prime is 3100121200219. The next prime is 3100121200223. The reversal of 3100121200221 is 1220021210013.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (3100121200219) and next prime (3100121200223).
It is a cyclic number.
It is not a de Polignac number, because 3100121200221 - 21 = 3100121200219 is a prime.
It is a super-3 number, since 3×31001212002213 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 3100121200221.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3100121200223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 516686866701 + ... + 516686866706.
It is an arithmetic number, because the mean of its divisors is an integer number (1033373733408).
Almost surely, 23100121200221 is an apocalyptic number.
It is an amenable number.
3100121200221 is a deficient number, since it is larger than the sum of its proper divisors (1033373733411).
3100121200221 is a wasteful number, since it uses less digits than its factorization.
3100121200221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1033373733410.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 3100121200221 its reverse (1220021210013), we get a palindrome (4320142410234).
The spelling of 3100121200221 in words is "three trillion, one hundred billion, one hundred twenty-one million, two hundred thousand, two hundred twenty-one".
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