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31001244145 = 554711335007
BaseRepresentation
bin11100110111110100…
…010111000111110001
32222000112022101010121
4130313310113013301
51001442304303040
622124120130241
72145145140664
oct346764270761
988015271117
1031001244145
1112169437633
126012306981
132c00949661
1417013db6db
15c169a3c4a
hex737d171f1

31001244145 has 8 divisors (see below), whose sum is σ = 37269506304. Its totient is φ = 24755653104.

The previous prime is 31001244143. The next prime is 31001244221. The reversal of 31001244145 is 54144210013.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31001244145 - 21 = 31001244143 is a prime.

It is a super-2 number, since 2×310012441452 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31001244143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5664769 + ... + 5670238.

It is an arithmetic number, because the mean of its divisors is an integer number (4658688288).

Almost surely, 231001244145 is an apocalyptic number.

It is an amenable number.

31001244145 is a deficient number, since it is larger than the sum of its proper divisors (6268262159).

31001244145 is a wasteful number, since it uses less digits than its factorization.

31001244145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11335559.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 31001244145 its reverse (54144210013), we get a palindrome (85145454158).

The spelling of 31001244145 in words is "thirty-one billion, one million, two hundred forty-four thousand, one hundred forty-five".

Divisors: 1 5 547 2735 11335007 56675035 6200248829 31001244145