Base | Representation |
---|---|
bin | 1001000001011100011… |
… | …10111011100000011001 |
3 | 1002122012100201221010112 |
4 | 10200232032323200121 |
5 | 20034401401423001 |
6 | 354230153054105 |
7 | 31253263444022 |
oct | 4405616734031 |
9 | 1078170657115 |
10 | 310013311001 |
11 | 10a526483039 |
12 | 500ba9b7335 |
13 | 233074c99c4 |
14 | 1100cd6bc49 |
15 | 80e67eacbb |
hex | 482e3bb819 |
310013311001 has 2 divisors, whose sum is σ = 310013311002. Its totient is φ = 310013311000.
The previous prime is 310013310979. The next prime is 310013311009. The reversal of 310013311001 is 100113310013.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 278307947401 + 31705363600 = 527549^2 + 178060^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-310013311001 is a prime.
It is a super-2 number, since 2×3100133110012 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (310013311009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155006655500 + 155006655501.
It is an arithmetic number, because the mean of its divisors is an integer number (155006655501).
Almost surely, 2310013311001 is an apocalyptic number.
It is an amenable number.
310013311001 is a deficient number, since it is larger than the sum of its proper divisors (1).
310013311001 is an equidigital number, since it uses as much as digits as its factorization.
310013311001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 14.
Adding to 310013311001 its reverse (100113310013), we get a palindrome (410126621014).
The spelling of 310013311001 in words is "three hundred ten billion, thirteen million, three hundred eleven thousand, one".
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