Base | Representation |
---|---|
bin | 100011001111110001011100… |
… | …1011111000001000000000101 |
3 | 1111122201200021121212122020011 |
4 | 1012133202321133001000011 |
5 | 311114022022442204424 |
6 | 3015214142311510221 |
7 | 122206000654102345 |
oct | 10637427137010005 |
9 | 1448650247778204 |
10 | 310031031209989 |
11 | 8a870470697931 |
12 | 2a932111088371 |
13 | 103cba5446c24b |
14 | 567b820d22d25 |
15 | 25c9942bc4694 |
hex | 119f8b97c1005 |
310031031209989 has 2 divisors, whose sum is σ = 310031031209990. Its totient is φ = 310031031209988.
The previous prime is 310031031209983. The next prime is 310031031210049. The reversal of 310031031209989 is 989902130130013.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 194424817576900 + 115606213633089 = 13943630^2 + 10752033^2 .
It is a cyclic number.
It is not a de Polignac number, because 310031031209989 - 217 = 310031031078917 is a prime.
It is a super-2 number, since 2×3100310312099892 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (310031031209983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155015515604994 + 155015515604995.
It is an arithmetic number, because the mean of its divisors is an integer number (155015515604995).
Almost surely, 2310031031209989 is an apocalyptic number.
It is an amenable number.
310031031209989 is a deficient number, since it is larger than the sum of its proper divisors (1).
310031031209989 is an equidigital number, since it uses as much as digits as its factorization.
310031031209989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 314928, while the sum is 49.
The spelling of 310031031209989 in words is "three hundred ten trillion, thirty-one billion, thirty-one million, two hundred nine thousand, nine hundred eighty-nine".
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