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310031301121 is a prime number
BaseRepresentation
bin1001000001011110100…
…11100011101000000001
31002122020121120220221021
410200233103203220001
520034421003113441
6354232034425441
731253602402243
oct4405723435001
91078217526837
10310031301121
1110a535650303
1250104a32281
132330b158349
14110114d2093
1580e81a13d1
hex482f4e3a01

310031301121 has 2 divisors, whose sum is σ = 310031301122. Its totient is φ = 310031301120.

The previous prime is 310031301059. The next prime is 310031301169. The reversal of 310031301121 is 121103130013.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 306571508721 + 3459792400 = 553689^2 + 58820^2 .

It is an emirp because it is prime and its reverse (121103130013) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 310031301121 - 213 = 310031292929 is a prime.

It is a super-2 number, since 2×3100313011212 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 310031301095 and 310031301104.

It is not a weakly prime, because it can be changed into another prime (310031305121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155015650560 + 155015650561.

It is an arithmetic number, because the mean of its divisors is an integer number (155015650561).

Almost surely, 2310031301121 is an apocalyptic number.

It is an amenable number.

310031301121 is a deficient number, since it is larger than the sum of its proper divisors (1).

310031301121 is an equidigital number, since it uses as much as digits as its factorization.

310031301121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 310031301121 its reverse (121103130013), we get a palindrome (431134431134).

The spelling of 310031301121 in words is "three hundred ten billion, thirty-one million, three hundred one thousand, one hundred twenty-one".